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Installing ns-3.37 and ns-3.35 in Ubuntu | Ubuntu 22.04 | NS3

Multiple Versions of ns3 in Ubuntu 22.04 In this post, we are going to install two versions of ns3 namely ns-3.35 and ns-3.37  My OS is : Ubuntu 22.04 LTS (Long Term Support) ns-3.35 uses waf and (./waf --run scratch/first)  ns-3.37 uses cmake  (./ns3 run scratch/first.cc) So we will install both the packages  Go through the video for complete instructions To start with  $ sudo apt update  $ sudo apt install build-essential autoconf automake libxmu-dev g++ python3 python3-dev pkg-config sqlite3 cmake python3-setuptools git qtbase5-dev qtchooser qt5-qmake qtbase5-dev-tools gir1.2-goocanvas-2.0 python3-gi python3-gi-cairo python3-pygraphviz gir1.2-gtk-3.0 ipython3 openmpi-bin openmpi-common openmpi-doc libopenmpi-dev autoconf cvs bzr unrar gsl-bin libgsl-dev libgslcblas0 wireshark tcpdump sqlite sqlite3 libsqlite3-dev  libxml2 libxml2-dev libc6-dev libc6-dev-i386 libclang-dev llvm-dev automake python3-pip libxml2 libxml2-dev libboost-all-dev  I have downloaded both the versions of ns3 fr

Stack Implementation using C

The following two programs for the stack implementation using Array and Linked List, the readers are requested to report if there are any errors (syntax or semantic)

//STACK IMPLEMENTATION USING ARRAYS\\

#include<stdio.h>

#include<conio.h>

void create(void);

void push(0void);

void pop(void);

void display(void);

void topelement(void);

int a[25];

int top;

void create()

{

int i;

printf("Enter the number of elements in the stack \n");

scanf("%d",&top);

printf("Enter the elements \n");

for(i=0;i<top;++i)

{

scanf("%d",&a[i]);

}

return;

}

void display()

{

int i;

if((top!=0) && (top!=25))

{

printf("The elements in the stack are \n");

for(i=top-1;i>=0;--i)

printf("%d",a[i]);

getch();

}

}

void push()

{

if(top==25)

{

printf("The stack is full \n");

}

else

{

printf("Enter the element \n");

scanf("%d",&a[top]);

top++;

}

return;

}

void pop()

{

if(top==0)

{

printf("the stack is empty \n");

}

else

{

printf("The popped element is %d",a[--top]);

}

return;

}

void topelement()

{

int t;

if(top==0)

{

printf("There is no top element \n");

}

else

{

t=top-1;

printf("The top element is %d\n",a[t]);

}

return;

}

void main()

{

int ch;

clrscr();

create();

display();

do{

clrscr();

printf("Stack operations \n");

printf("----------------\n");

printf("1. PUSH \n");

printf("2. POP \n");

printf("3. TOP ELEMENT \n");

printf("4. Displaying the stack \n");

printf("5. Quit \n");

printf("Enter your choice \n");

scanf("%d\n",&ch);

switch(ch)

{

case 1: push();

display();

break;

case 2: pop();

display();

break;

case 3: topelement();

// display();

break;

case 4: display();

break;

case 5: printf("END \n");

break;

default: printf("Invalid Entry \n");

}

getch();

}while(ch !=5);

}

Sample output:

Enter the number of elements in the stack

4

Enter the elements

1

2

3

4

The elements in the stack are

4321

Stack operations

----------------

1. PUSH

2. POP

3. TOP ELEMENT

4. Displaying the stack

5. Quit

Enter your choice

1

0

Enter the element

The elements in the stack are

04321

Enter your choice

3

The top element is 0

Enter your choice

2

The popped element is 0

Enter your choice

1

Enter the element

1

The elements in the stack are

14321

Enter your choice

5

END

 

STACK USING LINKED LIST

#include<stdio.h>

#include<conio.h>

#include<stdlib.h>

typedef struct node

{

int data;

struct node *next;

}stack;

int size();

void view();

int isFull();

int isEmpty();

void displayMenu();

int push(int value);

int pop(int *value);

int peek(int *value);

stack *getNode();

void releaseNode(stack *newnode);

stack *topstk=NULL;

void main()

{

int data,status,choice;

displayMenu();

while(1)

{

printf("\n\n ?");

scanf("%d",&choice);

switch(choice)

{

case 1:

printf("\nenter the element:");

fflush(stdin);

scanf("%d",&data);

status=push(data);

if(status == -1)

printf("\n memory is not available.....");

break;

case 2:

status=pop(&data);

if(status == -1)

printf("\nstack is underflow on pop");

else

printf("\n the popped elementis %d",data);

break;

case 3:

status=peek(&data);

if(status == -1)

printf("\nstack is empty!!!");

else

printf("\n the top element is %d",data);

break;

case 4:

printf("\ncurrent stack element = %d",size());

break;

case 5:

view();

break;

default:

printf("\n end of run program");

exit(0);

}

}

}

void displayMenu()

{

printf("\nrepresentation of stack using single linked list");

printf("\n\t1.push");

printf("\n\t2.pop");

printf("\n\t3.peek");

printf("\n\t4.size");

printf("\n\t5.view");

printf("\n\t6.exit");

}

stack *getNode()

{

return((stack *)malloc(sizeof(stack)));

}

void releaseNode(stack *newnode)

{

free(newnode);

}

int push(int value)

{

extern stack *topstk;

stack *newptr;

if(isFull())

return -1;

newptr=getNode();

newptr->data=value;

newptr->next=topstk;

topstk=newptr;

return 0;

}

int pop(int *value)

{

extern stack *topstk;

stack *temp;

if(isEmpty())

return -1;

temp=topstk;

topstk=topstk->next;

*value=temp->data;

releaseNode(temp);

return 0;

}

int peek(int *value)

{

extern stack *topstk;

stack *temp;

if(isEmpty())

return -1;

temp=topstk;

*value=temp->data;

return 0;

}

int isEmpty()

{

extern stack *topstk;

if(topstk==NULL)

return 1;

else

return 0;

}

int isFull()

{

extern stack *topstk;

stack *temp;

temp=getNode();

if(temp==NULL)

return 1;

else

{

releaseNode(temp);

return 0;

}

}

int size()

{

extern stack *topstk;

stack *top;

int count=0;

for(top=topstk;top!=NULL;top=top->next)

count++;

return count;

}

void view()

{

extern stack *topstk;

stack *top;

if(isEmpty())

{

printf("\nthe stack is empty!!!");

return;

}

printf("\n the content of the stack is......TOP");

for(top=topstk;top!=NULL;top=top->next)

printf("-->%d",top->data);

}

Sample output:

Representation of stack using linked list

1. Push

2. Pop

3. Peek

4. Size

5. View

6. Exit

?2

stack underflow on POP

?3

stack is empty

?4

stack is elements=0

?1

enter the element:11

?1

enter the element:22

?5

the content of the stack is……TOPà22à11

?4

stack elements=2

?2

the popped value is 22

?6

end of run of your program

Comments

  1. Sir, i am regular reader of this site. Very usefull information for college assignments

    ReplyDelete
  2. yeah, welcome, also visit http://www.acadprojects.com

    ReplyDelete

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